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In an adsorption experiment, a graph between log (x/m) versus log P was found to be linear with a slope of 45°. The intercept on the log (x/m) was found to be 0.3010. The amount in grams of the gas adsorbed per gram of charcoal under a pressure of 0.5 atm is

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Detailed Solution

According to the Freundlich equationxm=KP1/nor logxm=logK+1nlogP Plot of log⁡xm versus log⁡P is linear with slope Thus, 1n=tan⁡θ=tan⁡45∘=1 or n=1log⁡K=0.3010 or K= antilog 0.3010=2At P = 0.5 atmxm=KP1/n=2×0.51=1.0

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