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In an adsorption experiment, a graph between log (x/m) versus log P was found to be linear with a slope of 45°. The intercept on the y axis was found to be 0.301 . Calculate the amount of the gas adsorbed per gram of charcoal under a pressure of 3.0 atm.

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answer is 6.

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Detailed Solution

log⁡xm=log⁡K+1nlog⁡P∴ Plot of log⁡xm versus log⁡P is linear with slope =1n and intercept - log k Thus 1n=tan⁡θ=tan⁡45∘=1 or n=1Log K= 0.301 or K= antilog 0.301 = 2At P=3 atmxm=KP1/n=2×(3)1=6

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In an adsorption experiment, a graph between log (x/m) versus log P was found to be linear with a slope of 45°. The intercept on the y axis was found to be 0.301 . Calculate the amount of the gas adsorbed per gram of charcoal under a pressure of 3.0 atm.