First slide

Electrolysis

Question

After the electrolysis of aqueous solution of NaCl using Pt electrodes, the pH of the solution

Easy

A

increases
B

decreases
C

remains constant
D

becomes zero

Solution

$2NaCl \rightleftharpoons 2N{a^ + } + 2C{l^ - }$

At Cathode
$SRP\,\,of\,\,{H_2}O > SRP\,of\,N{a^ + }$
H₂O under goes reduction.
$2{H_2}O \rightleftharpoons {H_2} + 2O{H^ - } - 2{e^ - }$
At Anode
$SOP\,\,of\,\,C{l^ - } > SOP\,of\,{H_2}O$
Cl^- undergoes oxidation.
$2C{l^ - } - 2{e^ - } \rightleftharpoons C{l_2}$
In the vessel Na⁺and OH^- reacts with each other and forms NaOH,which is a strong base. P^H increases.

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