Air contains 20% by volume of oxygen. The volume of air required for the complete combustion of 1L of methane under the same conditions is

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2 lit

4 lit

10 lit

0.4 lit

answer is C.

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Detailed Solution

CH4(g) +2O2g)→CO2(g)+2H2O(l)Volume of O2 required = 2litersVolume present of O2 in air = 20% Volume of air required =220×100=10 lit

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