Q.

Air contains O2 and N2 in the ratio 0.2 : 0.8. If Henry law constant for O2 and N2 are 3.3 × 107 torr and 6.6 × 107 torr respectively, then the ratio of mole fractions of O2 to N2 dissolved in water at 1 bar pressure is

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answer is 3.

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Detailed Solution

mole ratio of  O2 : N2 in air =0.2 : 0.8 = 1:4We know                 Given              According to Henry's law                                     where    XA = molefraction of gas dissolved in liquid                                   Thus ratio of molefraction of O2 to N2 dissolved in water is  1:2
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Air contains O2 and N2 in the ratio 0.2 : 0.8. If Henry law constant for O2 and N2 are 3.3 × 107 torr and 6.6 × 107 torr respectively, then the ratio of mole fractions of O2 to N2 dissolved in water at 1 bar pressure is