The air is a mixture of a number of gases. The major components of air are oxygen and nitrogen with approximate proportion of 20% to 79% by volume at 298 K. The water is in equilibrium with air at a pressure of 10 atm. At 298 K, if the Henry's law constants for oxygen and nitrogen are 330 x 107 mm and 6.51 x 107 mm respectively, calculate the composition of these gases in water.

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N2=4.6×10−5; O2=9.22×10−5

N2=2.3×10−5; O2=4.8×10−5

N2=9.22×10−5;O2=4.6×10−5

N2=4.8×10−5; O2=2.3×10−5

answer is C.

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Detailed Solution

p=xptotal ;pO2=10×20100=2atm=2×760mm pN2=10×79100=7.9atm=7.9×760mmxO2=pO2KH=2×760mm3.3×107mm=4.6×10−5xN2=pN2KH=7.9×760mm6.51×107mm=9.22×10−5

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