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Al2O3 is reduced by electrolysis at low potentials and high currents. If 4.0×104 amperes of current is passed through molten Al2O3 for 6 hours, what mass of aluminium is produced? (Assume 100% current efficiency. Atomic mass of Al = 27 g mol-1)

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a

1.3×104 g

b

9.0×103 g

c

8.05×104 g

d

2.4×105 g

answer is C.

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Detailed Solution

Eq. of Al formed =mF=it96500∴ mAl=4×104×6×60×60×2796500×3(E=273)∴ mAl=8.05×104 g

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Al2O3 is reduced by electrolysis at low potentials and high currents. If 4.0×104 amperes of current is passed through molten Al2O3 for 6 hours, what mass of aluminium is produced? (Assume 100% current efficiency. Atomic mass of Al = 27 g mol-1)