Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

All the energy released from the reaction X→Y,ΔrG0=−193kJ mol-1 is used for oxidizing M+ as  M+→M3++2e−,E0=−0.25V             Under standard conditions, the number of moles of M+ oxidized when one mole of X is converted to Y is F=96500 C mol−1

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

answer is 4.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

ΔG0=−nFE0cellΔG0=−2×96,500×(−0.25)=+0.5×96,500=48,250=48,250kJFor conversion of mole of M+→M+3The requirement is 48,250 kJ \ with 193 kJ; no. of moles of  M+ oxidized is equal to 193/48.25 = 4
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring