The ammonia evolved from the treatment of 0.30 g of an organic compound for the estimation of nitrogen was passed in 100 mL of 0.1 M sulphuric acid. The excess of acid required 20 mL of 0.5 M sodium hydroxide solution for complete neutralization. The organic compound is
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a
Urea
b
Benzamide
c
Acetamide
d
Thiourea
answer is A.
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Detailed Solution
Equivalent of NH3 evolved = 100 × 0.1 × 21000 - 20 × 0.51000 = 1100percent of nitrogen in the unknown organic compound= 1100 × 140.3 × 100 = 46.6%percent of nitrogen in urea NH22CO= 14 × 260 × 100 = 46.6 % ∴ The compound must be urea.