The ammonia evolved from the treatment of $$0.35$$ gm of an organic compound for the estimation of $$N2$$ was passed in $$100ml$$ of $$0.1$$ M sulphuric acid. The excess of acid required $$20$$ ml of $$0.5$$ M NaOH for complete neutralization. The % of ‘N’ is

Question

The ammonia evolved from the treatment of $$0.35$$ gm of an  organic compound for the estimation of $$N2$$ was passed in $$100ml$$ of  $$0.1$$ M sulphuric acid. The excess of acid required $$20$$ ml of $$0.5$$ M NaOH for  complete neutralization. The % of ‘N’ is

Infinity Learn · Accepted Answer

Milli equivalence of $$H2SO4$$     taken for absorption of $$NH3=N$$×$$V=100$$×$$0.2$$       Milli equivalence of $$H2SO4$$     left after absorption of $$NH3=$$     M.eq of NaOH     used for $$H2SO4=20$$×$$0.5$$     M.eq of $$H2SO4$$     used for neutralization of $$NH3$$     $$=(100$$×$$0.2)$$−(20$$×$$0.5)                                                                                          $$=20$$−$$10=10=NV$$                                                                                 %  $$N=1.4$$×$$100.35=40$$

The ammonia evolved from the treatment of 0.35 gm of an organic compound for the estimation of N2 was passed in 100ml of 0.1 M sulphuric acid. The excess of acid required 20 ml of 0.5 M NaOH for complete neutralization. The % of ‘N’ is

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