The ammonia evolved from the treatment of 0.35 gm of an organic compound for the estimation of N2 was passed in 100ml of 0.1 M sulphuric acid. The excess of acid required 20 ml of 0.5 M NaOH for complete neutralization. The % of ‘N’ is

Milli equivalence of H2SO4 taken for absorption of NH3=N×V=100×0.2 Milli equivalence of H2SO4 left after absorption of NH3= M.eq of NaOH used for H2SO4=20×0.5 M.eq of H2SO4 used for neutralization of NH3 =(100×0.2)−(20×0.5)                                                                                      =20−10=10=NV                                                                            %  N=1.4×100.35=40