The ammonia (NH3) released on quantitative reaction of 0.6 g urea (NH2CONH2) with sodium hydroxide (NaOH) can be neutralized by

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

100 mL of 0.2 N HCl

100 mL of 0.1 N HCl

200 mL of 0.4 N HCl

200 mL of 0.2 N HCl

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

2 × mole of Urea mole of NH3 …..(1)Mole of NH3 = mole of HCl …..(2)∴ mole of HCl = 0.02 mole

Watch 3-min video & get full concept clarity