The ammonia prepared by treating ammonium sulphate with calcium hydroxide is completely used by $$NiCl2.6H2O$$ to form a stable coordination compound. Assume that both the reactions are $$100$$% complete. If $$1584$$ g of ammonium sulphate and $$952$$ g of $$NiCl2.6H2O$$ are used in the preparation, the combined weight (in$$ $$grams) of gypsum and the $$nickel-ammonia$$ coordination compound thus produced is (Atomic$$ weights in g $$mol-1$$: H $$=$$ $$1$$, N $$=$$ $$14$$, O $$=$$ $$16$$, S $$=$$ $$32$$, Cl $$=$$ $$35.5$$, Ca $$=$$ $$40$$, Ni $$=$$ $$59)

Question

The  ammonia  prepared  by  treating  ammonium  sulphate  with  calcium  hydroxide  is completely used by $$NiCl2.6H2O$$ to form a stable coordination compound. Assume that both the reactions are $$100$$% complete.  If $$1584$$ g of ammonium sulphate and $$952$$ g of $$NiCl2.6H2O$$ are used in the preparation, the combined weight  (in$$ $$grams) of gypsum and the $$nickel-ammonia$$ coordination compound thus produced is (Atomic$$ weights in g $$mol-1$$: H $$=$$ $$1$$, N $$=$$ $$14$$, O $$=$$ $$16$$, S $$=$$ $$32$$, Cl $$=$$ $$35.5$$, Ca $$=$$ $$40$$, Ni $$=$$ $$59)

Infinity Learn · Accepted Answer

(NH4)2$$ $$SO4+$$ $$Ca(OH)2$$ → $$CaSO4.2H2O+2NH3$$               $$1584$$ g                           gypsum $$($$ M $$=172) $$24mole$$              $$=12$$ mol                             $$12$$ mol $$NiCl2.6H2O952g=4mol+6NH324mol$$→$$NiNH36M=2324molCl2+6H2OTotal$$ mass $$=12$$×$$172+4$$×$$232=2992g$$

Best Courses for You

Detailed Solution

courses

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

download the app

Download the App