Q.

Ammonia under a pressure of 15atm at 27oC is heated to 347oC in a closed vessel in the presence of a catalyst. Under the conditions, NH3 is partially decomposed according to the equation, 2NH3⇌N2+3H2 the vessel is such that the volume remains effectively constant where as pressure increases to 50 atm. Calculate the percentage of NH3. actually decomposed :

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a

65%

b

61.3%

c

63.5%

d

64%

answer is B.

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Detailed Solution

NH3 ⇌ 12N2 + 32H2   Total no. of moles Initially;   1mol        0          0              1   at equil.; 1-x        x/2      3x/2        1+xFrom ideal gas equation, PV=nRT at constant V , nTP=constant   i.e. n1T1P1=n2T2P2 1×30015=(1+x)62050 x=0.613∴% of dissociation = 61.3%
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Ammonia under a pressure of 15atm at 27oC is heated to 347oC in a closed vessel in the presence of a catalyst. Under the conditions, NH3 is partially decomposed according to the equation, 2NH3⇌N2+3H2 the vessel is such that the volume remains effectively constant where as pressure increases to 50 atm. Calculate the percentage of NH3. actually decomposed :