Among the triatomic $$molecules/ions$$,$$BeCl2$$,$$N3$$−,$$N2O$$,$$NO2+$$,$$O3$$,$$SCl2$$,$$ICl2$$−,$$I3$$−and $$XeF2$$ the total number of linear $$molecule(s)/ion(s)$$ where the hybridization of the central atom does not have contribution from the $$d-orbital(s)$$ is : [Atomic number :$$S=16$$,$$Cl=17$$,$$I=53$$ and $$Xe=54$$ ]

Question

Among the triatomic $$molecules/ions$$,$$BeCl2$$,$$N3$$−,$$N2O$$,$$NO2+$$,$$O3$$,$$SCl2$$,$$ICl2$$−,$$I3$$−and $$XeF2$$ the total number of linear $$molecule(s)/ion(s)$$ where the hybridization of the central atom does not have contribution from the $$d-orbital(s)$$ is : [Atomic number :$$S=16$$,$$Cl=17$$,$$I=53$$ and $$Xe=54$$ ]

Infinity Learn · Accepted Answer

$$BeCl2$$,$$N3$$−,$$N2O$$,$$NO2+$$,$$O3$$,$$SCl2$$,$$ICl2$$−,$$I3$$−,$$XeF2BeCl2$$⟶sp⟶ linear;                  $$N3$$−⟶sp⟶ linear $$N2O$$⟶sp⟶ linear;                     $$NO2$$⟶sp⟶ linear $$O3$$⟶$$sp2$$⟶ bent;                        $$SCl2$$⟶$$sp3$$⟶ bent $$I3$$−⟶$$sp3d$$⟶ linear;                     $$ICl2$$−⟶$$sp3d$$⟶ linear $$XeF2$$⟶$$sp3d$$⟶ linear     There are four (4) linear $$molecules/ions$$ and no $$d-$$ orbital is involved in hybridization.

Covalent Bonding

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Covalent Bonding

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Among the triatomic molecules/ions,BeCl2,N3−,N2O,NO2+,O3,SCl2,ICl2−,I3−and XeF2 the total number of linear molecule(s)/ion(s) where the hybridization of the central atom does not have contribution from the d-orbital(s) is : [Atomic number :S=16,Cl=17,I=53 and Xe=54 ]

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