Amongst the following the compound that is both paramagnetic and coloured is
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a
K2Cr2O7
b
NH42TiCl6
c
CoSO4
d
K3Cu(CN)4
answer is C.
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Detailed Solution
In NH42TiCl6,Ti4+3 d04 s0 has no unpaired electrons. In K2Cr2O7,Cr6+3p6 d0 has no unpaired electrons. In CoSO4,Co2+d7 has unpaired electrons in d-orbitals, so it is both paramagnetic and coloured. In K3Cu(CN)4,Cu+3 d10, has no unpaired electron.