The amount of BaSO4 formed upon mixing 100 ml of 20.8% by weight BaCl2 solution with 50ml of 9.8% by weight H2SO4 solution will be ____?(Ba =137, Cl = 35.5., S= 32, H = I and O=16)
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a
23.3g
b
11.65 g
c
30.6g
d
33.2g
answer is B.
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Detailed Solution
BaCl2+H2SO4→BaSO4+2HCl Weight of BaCl2=20.8 g;weight of H2SO4=9.8%= 4.9gm , BaCl2+H2SO4→BaSO4+2HCl 0.1 0.05 0.05Weight of BaSO4=0.05×233=11.65g