The amount of energy released when 106 atoms of iodine in vapour state are converted to I- ions is 4.9×10−13J. What will be electron affinity of iodine in eV per atom
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answer is 3.06.
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Detailed Solution
Energy released for 106 atoms =4.9×10−13J Energy released for 1 atom=4.9×10−13106J=4.9×10-13×10−61.6×10−19=3.06eV.
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The amount of energy released when 106 atoms of iodine in vapour state are converted to I- ions is 4.9×10−13J. What will be electron affinity of iodine in eV per atom