Amount of Ferrous oxalate that reacts with one mole of acidified KMnO4 is___?

Writing the half reactions of reduction and oxidation,2KMnO4+3H2SO4+5e−→K2SO4+2MnSO4+3H2O×32FeC2O4+3H2SO4→Fe2SO43+3H2O+4CO2+3e−×5On adding the above two half reactions, we get the complete balanced redox reaction.6KMnO4+24H2SO4+10FeC2O4→5Fe2SO43+3K2SO4+6MnSO4+24H2O+20CO2Then number of moles of Ferrous oxalate that react with one mole of  KMnO4 is 10/6=1.66Gram molecular weight of Ferrous oxalate is = 144 gm per moleSo, mass of Ferrous oxalate that react with one mole of KMnO4 =1.66×144=239 gram