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Q.

An amount of 20g potassium sulphate was dissolved in 150 cm3 of water. The solution was then electrolysed. After electrolysis the content of potassium sulphate in the solution was 15% by mass. Determine volume of the gases obtained at NTP ? ( dH2O = 1 g cm–3)

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a

45.6 L H2 gas

b

22.8 L O2 gas

c

42 L H2 gas

d

None of these

answer is A.

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Detailed Solution

An amount of 20g . . . . . .Before electrolysis mass (H2O) = 150 gAfter electrolysismH2O=150−113.3=36.7gnH2O=2.04molSince,2H2O→2H2+O2 nH2=2.04mol V=45.6LnO2=1.02mol. V=22.8L

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