First slide

Electrolytic cells

Question

An amount of 20g potassium sulphate was dissolved in 150 cm3 of water. The solution was then electrolysed. After electrolysis the content of potassium sulphate in the solution was 15% by mass. Determine volume of the gases obtained at NTP ? ( d_H2O = 1 g cm^–3)

Moderate

A

45.6 L H₂ gas
B

22.8 L O₂ gas
C

42 L H₂ gas
D

None of these

Solution

An amount of 20g . . . . . .
Before electrolysis mass (H₂O) = 150 g
After electrolysis
$m (H_{2} O) = 150 - 113.3 = 36.7 g$
$n_{H_{2} O} = 2.04 mol$
Since,
$\begin{array}{ll} 2 H_{2} O \to 2 H_{2} + O_{2} \\ n_{H_{2}} = 2.04 mol V = 45.6 L \\ n_{O_{2}} = 1.02 mol . V = 22.8 L \end{array}$

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