The amount of ice that will separate out on cooling the solution containing 50g of ethylene glycol (CH2OH)2 in 200 g of water at -9.30C is (Kf for water = 1.86 K mol-1)

Wt. of Ethylene glycol = 50gGMW of Ethylene glycol [C2H4(OH)2] =62gWt. of H2O taken = 200gFP of aqueous sol. = -9.3ocOnly excess water separates out as ice, Let the amount of H2O required to dissolve50g of Ethylene glycol be XExcess water = (200-X)gX = 161.3gExcess water separating as ice = (200-161.3)=38.7g