Q.

The amount of water produced (in g) in the oxidation of 1 mole of rhombic sulphur by conc.HNO3 to a compound with the highest oxidation state of sulphur is ____ (Given data : Molar mass of water = 18g mol-1) s

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answer is 288.

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Detailed Solution

S8 + HNO3 → H2SO4 + NO2 + H2ORhombic SulphurBalancing the equationS8 + 48HNO3 → 8H2SO4 + 48NO2 + 16H2ORhombic Sulphur1 mole S8 produces 16 x 18 gm of H2O i.e. 288 gms of H2O.
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