On analysis of an impure example of sodium chloride, the percentage of chlorine was found to be 45.5. What is the percentage of pure sodium chloride in the given sample?
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answer is 75.
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Detailed Solution
The molecular mass of pure sodium chorine (NaCl)= At. Mass of Na + At. Mass of chlorine = (23 + 35.5) = 58.5% of chlorine is pure NaCl=35.558.5×100=60.6Thus,% of purity of NaCl in the sample =45.560.6×100=75