Aqueous solution of barium phosphate which is 100% ionised has ΔTf/Kf as 0.05. Hence, given solution is

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0.01 molal

0.02 molal

0.04 molal

0.05 molal

answer is A.

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Detailed Solution

Ba3(PO4)2⇌3Ba2++2PO43−value of i = 5 (100% ionised) so ΔTf=ikfmso m=ΔTfikf=0.055=0.01

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