First slide

13th group or boron group

Question

An aqueous solution of BCl₃ is:

Moderate

A

Weak acid
B

Weak base
C

Neutral
D

Strong base

Solution

BCl₃ + 3H₂O→ B(OH)₃ + 3HCl
B(OH)₃ + H₂O→[B(OH)₄]- + H⁺
B(OH)₃ due to its incomplete octet accepts an electron pair (as OH-) to give [B(OH)₄]-.
Boron in this ion involves one 2s orbital and three 2p orbitals. Thus, hybridization of B in [B(OH)4]- is sp³.

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