Aqueous solution of CuCl2  is subjected to electrolysis using Pt electrodes. Then the correct statement is

AqCuCl2  is a salt  of  SA−WB. It's  pH < 7On electrolysis  At Cathode                              Discharge potential of Cu+2 is  less  than  H2O∴  Cu+2 +2e− → Cu            At Anode                       Discharge potential of  Cl− is  less than  H2O2Cl− → Cl2+2e−∴ The  left  over  solution  will  be  H2O with  pH = 7pH<7  changes to  PH = 7pH   progressively  increases