First slide

Electrolysis

Question

Aqueous solution of CuSO₄ is electrolysed using inert electrodes till the blue coloured solution becomes colourless. The colourless solution formed is

Easy

A

Cu(OH)₂
B

H₂SO₄
C

CuSO₄
D

H₂O

Solution

$CuS{O_4} \rightleftharpoons C{u^{ + 2}} + SO_4^{ - 2}$
At Cathode
SRP of Cu⁺² > SRP of H₂O. Cu⁺² undergoes reduction.
$C{u^{ + 2}} + 2{e^ - } \rightleftharpoons Cu$
At Anode
$SOP\,\,of\,\,{H_2}O > SOP\,of\,SO_4^{ - 2}$
H₂O readily undergoes Oxidation
$2{H_2}O \rightleftharpoons {O_2} + 4{H^ + } + 4{e^ - }$
In the Vessel H⁺ reacts with $SO_{4}^{-2}$ and forms colorless solution H₂SO₄

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