First slide

Electrolysis

Question

Aqueous solution of CuSO₄ is subjected to electrolysis using copper electrodes. Correct statement about the process is

Easy

A

Hydrogen is liberated at cathode
B

Sulphur dioxide is liberated at anode
C

Copper decomposes at anode
D

Solution becomes alkaline

Solution

Attackable electrode is used.
At cathode $E_{{Cu}^{+ 2} / Cu}^{o} > E_{H^{+} / \frac{1}{2} H_{2}, Pt}^{o}$
${Cu}^{+ 2} + 2 \bar{e} \to Cu$
At anode $E_{Cu / {Cu}^{+ 2}}^{o} > E_{H_{2} O / O_{2}}^{o}$
$Cu \to {Cu}^{+ 2} + 2 \bar{e}$

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