Questions
An aqueous solution freezes at -2.55C. What is its boiling point = 0. 52 K m-1 ; Kf (H2O)= 1.86 K m-1
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a
107.0° C
b
100.6° C
c
100.1° C
d
100.7° C
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Correct option is D
∆Tf=2.55°C=Kf.m ∴m=2.55Kf ∆Tb=Kbm⇒∆Tb = 2.55×KbKf=2.55×0.521.86°C=0.7°C ⇒Tb=100+0.7=100.7°CSimilar Questions
Which of the following liquid pairs shows a positive deviation from Raoults law ?
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