First slide

Theory of dilute solutions

Question

An aqueous solution freezes at -2.55 $°$ C. What is its boiling point $K_{b_{(H_{2} O)}}$ = 0. 52 K m^-1 ; K_{f (H2O)}=1.86 K m^-1

Moderate

A

107.0 $°$ C
B

100.6 $°$ C
C

100.1 $°$ C
D

100.7 $°$ C

Solution

$∆ T_{f} = 2.55 ° C = K_{f} . m ∴ m = \frac{2.55}{K_{f}} ∆ T_{b} = K_{b} m \Rightarrow ∆ T_{b} = 2.55 \times \frac{K_{b}}{K_{f}} = 2.55 \times \frac{0.52}{1.86} ° C = 0.7 ° C \Rightarrow T_{b} = 100 + 0.7 = 100.7 ° C$

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