Q.
An aqueous solution freezes at – 0.1860C (Kf = 1.860; Kb = 0.5120). What is the elevation on boiling point?
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answer is 4.
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Detailed Solution
Method I : Given Tf(Fp of sol.) = -0.186oc Kf = 1.86 K Kg mole-1 , Kb= 0.512 K Kg mole-1 method-II :
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