First slide

Hydrogen Peroxide

Question

An aqueous solution of H₂O₂ is labeled as 33.6 vol. The amount of H₂O₂ present in 50ml of such an aqueous solution is

Easy

Solution

33.6 volume strength of H2O2 means,

$\large \\1ml\;of\;{H_2}{O_2}\;solution\;\xrightarrow{{\;gives\;}}\;33.6ml\;of\;{O_2}\\50ml\;of\;{H_2}{O_2}\;solution\;\xrightarrow{{\;gives\;}}\;??ml \;of\;{O_2}$

$\large \frac{50\times 33.6}{1}$
= 1680ml of O2 liberated from 50ml of H2O2 solution.

$\underset{2 moles}{H_{2} O_{2}} \to 2 H_{2} O + \underset{1 mole}{O_{2}}$
2 x 34 gr of $H_{2} O_{2}$ solutions → 22.4lit = 22400 ml
?? → 1680ml

$\large \frac{1680\times 2\times 34}{22400}\;=\;5.1gr\;of\;H_2O_2\;solution$

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