An aqueous solution of $$H2O2$$ is labeled as $$33.6$$ vol. The amount of $$H2O2$$ present in $$50ml$$ of such an aqueous solution is

$$33.6$$ volume strength of $$H2O2$$ means, $$=$$ $$1680ml$$ of $$O2$$ liberated from $$50ml$$ of $$H2O2$$ solution. $$2$$ x $$34$$ gr of $$H2O2$$ solutions → $$22.4lit$$ $$=$$ $$22400$$ ml?? → $$1680ml$$

Hydrogen Peroxide

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Question

An aqueous solution of H₂O₂ is labeled as 33.6 vol. The amount of H₂O₂ present in 50ml of such an aqueous solution is

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Solution

33.6 volume strength of H2O2 means,

$\large \\1ml\;of\;{H_2}{O_2}\;solution\;\xrightarrow{{\;gives\;}}\;33.6ml\;of\;{O_2}\\50ml\;of\;{H_2}{O_2}\;solution\;\xrightarrow{{\;gives\;}}\;??ml \;of\;{O_2}$

$\large \frac{50\times 33.6}{1}$
= 1680ml of O2 liberated from 50ml of H2O2 solution.

$\underset{2 moles}{H_{2} O_{2}} \to 2 H_{2} O + \underset{1 mole}{O_{2}}$
2 x 34 gr of $H_{2} O_{2}$ solutions → 22.4lit = 22400 ml
?? → 1680ml

$\large \frac{1680\times 2\times 34}{22400}\;=\;5.1gr\;of\;H_2O_2\;solution$

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Hydrogen Peroxide

Unlock the full solution & master the concept.

An aqueous solution of H2O2 is labeled as 33.6 vol. The amount of H2O2 present in 50ml of such an aqueous solution is

33.6 volume strength of H2O2 means, = 1680ml of O2 liberated from 50ml of H2O2 solution. H2O22 moles→2H2O+O21 mole2 x 34 gr of H2O2 solutions → 22.4lit = 22400 ml?? → 1680ml

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An aqueous solution of H₂O₂ is labeled as 33.6 vol. The amount of H₂O₂ present in 50ml of such an aqueous solution is