Aqueous solution of  Na2SO4 is subjected to electrolysis using inert electrodes. Then the true statement is

aq Na2SO4is a salt of SA – SB ∴pH = 7Due to electrolysis: At CathodeDischarge potential of  H2Ois lesser than Na+∴2H2O+2e− → H2+2OH−At AnodeDischarge potential of  H2O is lesser than SO 4−22H2O → 4H++4e−+O2          Left over solution is concentrated Na2SO4 . Composition doesn’t change but concentration increases.  pH of a salt of SA-SB always is 7 irrespective of its concentration.