Aqueous solution of two compounds A-O-H and B-O-H are taken separately. If the EN of A = 3.0, B = 1.5, O = 3.5 and H = 2.1, then the nature of two solutions will be respectively.

(i) EN difference between (O-A) = 3.5 -3.0 = 0.5, which indicates (A-O) bond will be covalent. Thus in (A-OH), O-H bond will be more ionic, thus bond will break and H@ ions will be released and acidic solution is formed.(ii) EN difference between (O-B) = 3.5 -1.5 = 2.0 thus in (BO-H), (B-O) bond will be ionic, and (B-O) bond will break and OH⊝ will be released and basic solution is formed.