Questions
An arbitrary compound decomposes according to reaction:
If one starts the decomposition reaction with 4 moles of and value of equilibrium constant is numerically equal to total pressure at equilibrium. Then which option is/are correct at equilibrium,.
detailed solution
Correct option is A
2P2Q ⇌ 2P2+Q2t=0 4 0 0t=eq 4(1−α) 4α 2αKp=4α4+2α×P22α4+2α×P4(1−α)4+2α×P2=2α3(1−α)2(4+2α)×PBut, Kp=P( given )∴2α3=(1-α)2(4+2α)∴-6α+4=0∴α=(2/3)Total moles at eq= 4+2α=(16/3)nP2Q=nQ2=(4/3), nP2=(8/3)\ Total number of moles of products = 83+43=123=4.Similar Questions
Which are true for the reaction :
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