Arrange the carbanions, CH33C¯, C¯Cl3, CH32 C¯H, C6H5C¯H2, in order of their decreasing stability
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a
C6H5C¯H2 > C¯Cl3 > CH33C¯ >CH32 C¯H
b
CH32 C¯H > C¯Cl3 >C6H5C¯H2 >CH32C¯
c
C¯Cl3 >C6H5C¯H2 >CH32C¯H>CH33C¯
d
CH32C¯ >CH32C¯H>C¯H2 >C¯Cl3
answer is C.
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Detailed Solution
−I effect [e− withdrawing] exerting groups stabilize carbanion by the dispersal of their -ve charge while +I effect exerting [e− releasing] groups destabilize the carbanion by increasing electron density on them. On the other hand, resonance stabilized carbanion are stable due to the involvement of their lone pair of electron with the delocalization of π−electrons of attached phenyl group.Thus,