Arrange the compounds I, II and III in decreasing order of their heats of combustion
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a
I>II>III
b
I>III>II
c
III>II>I
d
II>I>III
answer is C.
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Detailed Solution
More the number of carbons in alkane more will be the heats of combustion of the corresponding alkane. The following has highest number of carbons in the option.