Arrange the following aqueous solutions in the order of their increasing boiling points.I. 10-2MNaClII.10-3M MgCl2III.10-4M UreaIV.10-4M NaCl
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a
I
b
III
c
II
d
IV
answer is B.
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Detailed Solution
More the value of i, more will be the elevation in boiling point. Again, more dilute solution has low boiling point. Hence, increasing order of boiling points is:10-4m Urea <10-4M NaCl<10-3M MgCl2 <10-2M NaCl (i=1) (i=2) (i=3) (i=2)