Arrange the following in decreasing order of basic strength. (I) C6H5NH2 (II) p−NO2−C6H4−NH2 (III) Cyclohexyl amine
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answer is 4.
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Detailed Solution
Lone pair of nitrogen is delocalised in both aniline and p-nitroaniline, hence less basic than cyclohexyl amine. Strong electron withdrawing nitro group further decreases basic strength of aniline.