Q.

Arrange the following in the decreasing order of their boiling points:I. C9H20                       II. C8H18

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a

(I) > (II) > (III) > (IV)

b

(IV) > (III) > (II) > (I)

c

(I) > (II) > (IV) > (III)

d

(II) > (IV) > (II) > (I)

answer is A.

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Detailed Solution

The greater the number of C atoms and straight chain, the higher is the boiling point. So, I is greater than II. More is the branching, less is the surface area, so lower is the boiling point. Therefore, III is greater than IV.
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