Q.
Arrange the following in the decreasing order of their boiling points:I. C9H20 II. C8H18
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a
(I) > (II) > (III) > (IV)
b
(IV) > (III) > (II) > (I)
c
(I) > (II) > (IV) > (III)
d
(II) > (IV) > (II) > (I)
answer is A.
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Detailed Solution
The greater the number of C atoms and straight chain, the higher is the boiling point. So, I is greater than II. More is the branching, less is the surface area, so lower is the boiling point. Therefore, III is greater than IV.
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