Arrange the following in the increasing order of their bond order O2,O2+,O2− and O2-2

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O2−, O22−, O2+, O2

O2+, O2, O2−, O22−

O2, O2+, O2−, O22−

O2−2, O2−, O2, O2+

answer is D.

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Detailed Solution

Molecular orbital electronic configuration of O2 is (σ1s)2(σ∗1s)2(σ2s)2(σ∗2s)2σ2pz2(π2px)2(π2py)2(π∗2px)1(π∗2py)1 ∴ B.O. of O2=12(10−6)=2Molecular orbital electronic configuration of O2+ is : (σ1s)2σ∗1s2(σ2s)2σ∗2s2σ2pz2(π2px)2(π2py)2(π∗2px)1∴ B.O. of O2+=12(10−5)=2.5Molecular orbital electronic configuration of O2 is (σ1s)2σ∗1s2(σ2s)2σ∗2s2σ2p22(π2px)2(π2py)2(π∗2px)2(π∗2py)1∴ B.O. of O2−=12(10−7)=1.5Molecular orbital electronic configuration of O22- is (σ1s)2σ∗1s2(σ2s)2σ∗2s2σ2pz2(π2px)2(π2py)2(π∗2px)2(π∗2py)2∴ B.O. of O22−=12(10−8)=1.0∴ Increasing order of B.O. is O22−

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