Q.

Arrange the following in the increasing order of their solubility in n-octane based on solute-solvent interactions.

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a

KCI < CH3CN < CH3OH < cyclohexane

b

KCI < cyclohexane< CH3OH < CH3CN

c

KCI < CH3OH< CH3CN < cyclohexane

d

KCI < cyclohexane< CH3CN< CH3CN

answer is C.

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Detailed Solution

KCI < CH3OH < CH3CN < cyclohexane(i) Cyclohexane and n-octane both are non-polar, so they will mix completely.(ii) KCI is an ionic compound, while octane is non-polar organic compound, so KCI will not dissolve in n-octane.(iii) CH3OH and CH3CN both are polar but CH3CN will dissolve more than CH3OH in octane because CH3CN is less polar than CH3OH.
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Arrange the following in the increasing order of their solubility in n-octane based on solute-solvent interactions.