Arrange the following in order of decreasing N-O bond length : NO2+, NO2-, NO3-
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a
NO3- > NO2+ > NO2-
b
NO3- > NO2- > NO2+
c
NO2+ > NO3- > NO2-
d
NO2- > NO3- > NO2+
answer is B.
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Detailed Solution
N atom in NO2+ is sp hybridised while in NO2- and NO3-, it is sp2 hybridised.O = N = O Bond order = 2Bond order= 2+12=1.5 Bond order =2+1+13=1.33Bond order ∝1Bond LengthSo, Bond length order is NO3- > NO2- > NO2+