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Q.

Arrange the following in the order of increasing mass (Atomic mass of O = 16, Cu = 63 and N = l4).I. One atom of oxygenII. One atom of nitrogenIII 1 x 10-10 mole of oxygentV. 1x 10-10 mole of copper

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a

II< I< III< IV

b

I< II< III< IV

c

III< II< IV< I

d

IV< II< III< I

answer is A.

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Detailed Solution

I. Mass of one atom of oxygen=166.022×1023=2.66×10-23 gII. Mass of one atom of nitrogen =146.022×1023=2.32×10-23 g III. Mass of 1×10-10 mole of oxygen =16×10-10 g IV. Mass of 1×10-10 mole of copper =63×10-10Hence, masses of atoms in increasing order :II
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