The arrangement of X- ions around A+ ion in solid AX is given in the figure (not drawn to scale). If the radius of X- is 250 pm, the radius of A+ is :

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104 pm

125 pm

183 pm

57 pm

answer is A.

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Detailed Solution

r+r−=0.414 for octahedral void. r+r−=0.414× 250 103.5 ≅ 104 pm

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