First slide

Crystal lattices and unit cells

Question

The arrangement of X^- ions around A⁺ ion in solid AX is given in the figure (not drawn to scale). If the radius of X^- is 250 pm, the radius of A⁺ is :

Moderate

A

104 pm
B

125 pm
C

183 pm
D

57 pm

Solution

$\frac{r_{+}}{r_{-}} = 0 .414 for octahedral void.$
$\frac{r_{+}}{r_{-}} = 0 .414$ × 250 103.5 $≅$ 104 pm

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