Q.

Aspirin is a pain reliever with pKa = 2.Two tablets each containing 0.09 g of aspirin are dissolved in 100 mL solution. pH will be

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a

0.5

b

1.0

c

0.0

d

2.0

answer is D.

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Detailed Solution

Aspirin is a weak acid =0.09×2g/100mL=1.8gL−1 =1.8180molL−1=0.01M pH( weak acid )=12pKa−log⁡C=12[2+2]=2
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