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Assume that 2×10−17 J of light energy is needed by the interior of the human eye to see an object. How many photons of yellow light with λ= 595.2 nm and needed to generate this minimum energy?

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answer is 60.

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Detailed Solution

E=nhc(1240)λ(nm)⇒2×10−171.6×10−19=n×1240595.2⇒n=60

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