Assuming no change in volume, calculate the minimum mass of NaCl (in kg) necessary to dissolve 0.010 mol AgCl in 100 L solution.KfAgCl2−=3×105, Ksp=AgCl=1×10−10Molar mass of NaCl (58.5 g/mol)

AgCls             ⇌ Ksp                  Ag+aq  +   Cl−aq ∙                      X              a-2SAg+aq+2Cl−aq⇌ KF=3×105 AgCl2−aq x              a-2S                               S -------------------- AgClS  +     Cl−aq⇌ KspKFAgCl2−aq ∙               a-2S                   S=104 -------------------- 3×10−5=10−4a−2×10−4 a−2×10−4=103 a=103+2×10−4≃103 nNaCl100=103 WNaCl=58.53 Kg=19.5 Kg