Assuming pure 2s and 2p orbitals of carbon are used in forming CH4 molecule, which of the following statement is false?

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Three C-H bonds will be at right angle.

One C-H bond will be weaker than other three C-H bonds.

The shape of molecule will be tetrahedral.

The angle of C-H bond formed by s-s overlapping will be uncertain with respect to other three bonds.

answer is C.

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Detailed Solution

In the unhybridized state of carbon,2p orbitals are 90° to one another and each one will overlap with 1s orbital of three hydrogen atoms, thus three C-H bonds are formed which are 90° to one another. For the fourth hydrogen atom, its 1s orbital may overlap with non-directional 2s orbital of the carbon and this σ-bond will be stronger than σC-H bonds formed by 2p-ls overlap. In such situation CH4 molecule can never has tetrahedral geometry.

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