The atom which contains an electron with quantum number n=3,l=2,m=−1,s=−12 is:
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a
Li
b
F
c
V
d
Na
answer is C.
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Detailed Solution
The electronic configuration of given atoms is: 11Na=1s22s22p63s1. For n=3,l=2,m=−1 and s=−12, sub-shell is 3d. Since 3d is present in vanadium, V, the correct answer is (c).