The atomic mass and atomic number of lead are 208 and 82. The atomic mass and atomic number of bismuth are 209 and 83. The neutron/proton ratio in an atom
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a
Is higher in lead than in bismuth
b
Is lower in lead than in bismuth
c
Is equal in both lead and bismuth
d
None of these
answer is D.
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Detailed Solution
82Pb208;p=82;n=208−82=126 83Bi209;p=83;n=209−83=126n/p for Pb=12682=1.53n/p for Bi=12683=1.51∴np for Pb>np for Bi.