The atomic numbers of vanadium (V), Chromium (Cr), manganese (Mn) and iron (Fe) are respectively 23, 24, 25 and 26. Which one of these may be expected to have the highest second ionization enthalpy?
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a
Cr
b
Mn
c
Fe
d
V
answer is A.
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Detailed Solution
Cr(Z=24)...[Ar]4s13d5Cr+...........[Ar]3d5Cr+ acquires stability due to half filled 3d5 configuration.
The atomic numbers of vanadium (V), Chromium (Cr), manganese (Mn) and iron (Fe) are respectively 23, 24, 25 and 26. Which one of these may be expected to have the highest second ionization enthalpy?